Question
Expand the following:
$(3 a-5 b-c)^2$

Answer

$(3 a-5 b-c)^2=(3 a)^2+(-5 b)^2+(-c)^2+2(3 a)^2-5 b+2(-5 b)(-c)+2(-c)(3 a)$
${\left[\therefore a^2+b^2+c^2+2 a b+2 b c+2 c a=(a+b+c)^2\right]}$
$=9 a^2+25 b^2+c^2-30 a b+10 b c+6 c a .$

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