Question
Explain Anti-Markovnikov’s addition or peroxide effect or Kharasch-Mayo effect.
✓
Answer
In 1933, M. S. Kharasch and F. R. Mayo discovered that the addition of HBr to unsymmetrical alkene in the presence of organic peroxide (R-O-O-R) takes place in the opposite orientation to that suggested by Markovnikov’s rule.
e.g.
$H _3 C -\underset{\text { Propene }}{ CH }= CH _2+ H - Br \underset{\text { Benzoylperoxide }}{\left( C _6 H _5 CO _2 O _2\right.} \underset{\text { 1-Bromopropane }}{ H _3 C - CH _2- CH _2- Br }$
e.g.
$H _3 C -\underset{\text { Propene }}{ CH }= CH _2+ H - Br \underset{\text { Benzoylperoxide }}{\left( C _6 H _5 CO _2 O _2\right.} \underset{\text { 1-Bromopropane }}{ H _3 C - CH _2- CH _2- Br }$
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$i.$ If each molecule $($sphere$)$ represents a partial pressure of $1 \ atm,$ calculate the value of $K_P.$
$ii.$ Predict the change in equilibrium, when the volume is increased by $50$ percentage.
→$i.$ If each molecule $($sphere$)$ represents a partial pressure of $1 \ atm,$ calculate the value of $K_P.$
$ii.$ Predict the change in equilibrium, when the volume is increased by $50$ percentage.
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Answer:
Given: $t_{1 / 2}=78 h$,
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$N =100-12=88$
→Answer:
Given: $t_{1 / 2}=78 h$,
$N _0=100$,
$N =100-12=88$
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