Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsREPEATER 20242 Marks
Question
Explain Biot and Savart's law with suitable diagram.
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Answer
1.In the above figure, there is a current carrying wire of arbitrary shape, carrying a current I. The current in the differential length element $d l$ produces differential magnetic field $d \vec{B}$ at a point P at a distance $\vec{r}$ from the element $d l$. The $\otimes$ indicates that $d \vec{B}$ is directed into the plane of the paper. 2.According to Biot-Savart's law the strength of the magnetic field at any point due to current carrying conductor is directly proportional to current (1), current element (dl), sine and inversally proportional to distance from current element. $\therefore \quad d B=\frac{\mu_0}{4 \pi} \frac{I d l \sin \theta}{r^2}$ Above equation is known as Biot-Savart's law.
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