Chemical Thermodynamics — Chemistry STD 12 Science — Question
Maharashtra BoardEnglish MediumSTD 12 ScienceChemistryChemical Thermodynamics2 Marks
Question
Explain bond enthalpy of diatomic molecules.
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Answer
In case of diatomic molecules, since there is only one bond, the bond enthalpy is equal to heat of atomisation. For example, heat of atomisation of $HCl _{( g )}$ is $431.9 kJ mol ^{-1}$. $HCl _{( g )} \longrightarrow H _{( g )}+ Cl _{( g )} \quad \Delta_{ atm } H^0=431.9 kJ mol ^{-1}$ $\therefore$ Bond enthalpy of $HCl$, $\begin{aligned} \Delta_{\text {atm }} H^0 & =\frac{\Delta_{\text {atm }} H}{\text { Number of bonds broken }} \\ D_{ H - Cl } & =\frac{431.9}{1} \\ & =431.9 kJ mol ^{-1} \quad \end{aligned}$ (Bond enthalpy is generally denoted by D).
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