Question
Explain, by giving an example, how oxidation and reduction proceed side by side.
✓
Answer
$\text{CuO}\ \ \ \ \ \ \ \ \ \ \ +\ \ \ \ \ \ \ \ \ \text{H}_2\ \ \xrightarrow{\ \ \ \ \ {\text{Heat}}\ \ \ \ \ \ }\ \ \text{Cu}\ \ \ \ \ \ \ +\ \ \ \ \text{H}_2\text{O}\\ ^\text{Copper Oxide}\ \ \ \ \ \ \ \ \ \ \ \ ^\text{Hydrogen}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Copper}\ \ \ \ \ \ \ \ \ \ \ \ ^\text{Water}$
In this reaction, copper oxide is being reduced to copper whereas hydrogen is being oxidised to water.
In this reaction, copper oxide is being reduced to copper whereas hydrogen is being oxidised to water.
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