Question
Explain electrolysis of sulphuric acid.
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| Exp. | Initial $P(mol/L)$ | Initial $Q (mol/L)$ | Init. Rate of Formation of $R(M \ min-1)$ |
| $1$ | $0.10$ | $0.10$ | $3.0 \times 10^{-4}$ |
| $2$ | $0.30$ | $0.30$ | $9.0 \times 10^{-4}$ |
| $3$ | $0.10$ | $0.30$ | $3.0 \times 10^{-4}$ |
| $4$ | $0.10$ | $0.40$ | $6.0 \times 10^{-4}$ |
| t (sec) | P(mm of Hg) |
| $0$ | $35.0$ |
| $360$ | $54.0$ |
| $720$ | $63.0$ |