Question
Explain electrolysis of sulphuric acid.

Answer

→ In the electrolysis of dilute Sulphuric acid only electrolysis of water occurs.
$
\begin{array}{l}
2 H _2 O ( l ) \rightarrow O _2(g)+4 H ^{+}( aq )+4 e ^{-} E _{\text {(cell) }}^{\ominus}= \\+1.23 V\end{array}
$
→ Electrolysis of concentrated sulphuric acid oxidise $SO _4^{-2}$ ion $S _2 O _8^{-2}$
$
2 SO _4^{2-}( aq ) \rightarrow S _2 O _8^{2-}( aq )+2 e ^{-} E _{(\text {cell })}^{\ominus}=1.96 V
$

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