Question
Explain in short the wave particle duality of light (electromagnetic radiation).
✓
Answer
Wave particle duality of light (electromagnetic radiation):
- Light has both particle and wave like nature.
Phenomena such as diffraction and interference of light could be explained by treating light as electromagnetic wave. - However, the black-body radiation or photoelectric effect could not be explained by wave nature of light. This could be accounted for by considering particle nature of light. Thus, both phenomena could be explained only by accepting that light has dual behaviour.
- When light interacts with matter it behaves as a stream of particles (called photons) and when light propagates, it behaves as an electromagnetic wave.
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Round off each of the following quantities to three significant figures :
a. $1.43 cm^3$
b. $458 \times 10^2 cm$
c. $643 cm^2$
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e. $6.398 \times 10^{-3} km$
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→a. $1.43 cm^3$
b. $458 \times 10^2 cm$
c. $643 cm^2$
d. $0.039 m$
e. $6.398 \times 10^{-3} km$
f. $0.0179 g$
g. $79,000 m$
h. $42,150$
i. $649.85$
j. $23,642,000 mm$
k. $0.0041962 kg$
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→$ H _{ 2 ( g ) }+ I _{ 2 ( g )} \stackrel{ k _f}{\underset{ k _{ f }}{\rightleftharpoons}} 2 H I _{( g )}$
$K _{C}=54.0 \text { at } 700 K$
If $k _{ f }$ is the rate constant for the formation of $HI$ and $k _{ r }$ is the rate constant for the decomposition of $HI$, deduce whether $k _{ r }$ is larger or smaller than $k _{ r }$.
ii. If the value of $k_r$ at $700 K$ is $1.16 \times 10^{-3}$, what is the value of $k_f ?$