Question
Explain metal deficiency defect with example.
✓
Answer
Positive metal ions are missing from their original Lattice locations in some crystals. The existence of a cation of the same metal with a higher oxidation state than the missing cation balances the extra negative charge.
For Example: In $NiO$ one $Ni^{2+}$ ion is missing, creating a vacancy at its Lattice site. The deficiency of two positive charges is made up by the presence of two $Ni^{3+}$ ions at the other Lattice sites of $Ni^{2+}$ ions.
For Example: In $NiO$ one $Ni^{2+}$ ion is missing, creating a vacancy at its Lattice site. The deficiency of two positive charges is made up by the presence of two $Ni^{3+}$ ions at the other Lattice sites of $Ni^{2+}$ ions.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
State the first law of thermodynamics.
The normal boiling point of ethyl acetate is $77.06 ^\circ C.$ A solution of $50 g$ of non$-$volatile solute in $150 g$ of ethyl acetate boils at $84.27^\circ C.$ Evaluate the molar mass of solute if $K_b$ for ethyl acetate is $2.77 \ K \ kg \ mol^{-1}.$
→What is the action of acetic anhydride on aniline?
Answer the following
Write the formula to calculate the % atom economy.
Write the formula to calculate the % atom economy.
With the help of the equation, $\Delta G^0=-n F E_{\text {cell }}^0$ explain that cell potential is an intensive property.
→Benzyl alcohol to benzyl cyanide
Write the electronic configuration of $Cr$ and $Cu$.
→Fehling solution does not oxidise benzaldehyde but Tollen’s reagent oxidises benzaldehyde. Give reason.
Calculate the time required to deposit $2.4 g$ of $Cu,$ when $2.03 A$ of current passed through $CuSO_4,$ solution. $($At. mass of $Cu= 63.5 \ g \ mol^{-1})$
→What is the concentration of dissolved oxygen at $50^\circ C$ under pressure of one atmosphere if partial pressure of oxygen at $50^\circ C$ is $0.14 \ atm.$
$($Henry's law constant for oxygen $= 1.3 \times 10^{-3} \ mol \ dm^{-3} atm^{-1})$
→$($Henry's law constant for oxygen $= 1.3 \times 10^{-3} \ mol \ dm^{-3} atm^{-1})$