Question
Explain mutual induction using Faraday's two coil experiment. Obtain expression
✓
Answer
$\varepsilon_1=- M \frac{d l_2}{d t}$.
→In the figure, arrangement of two coil experiment is shown. Here, coils $C _1$ and $C _2$ are placed coaxially.
→When electric current $I _2$ passing through coil $C _2$ changes, magnetic flux linked with coil $C _1$ changes and hence induced emf $\varepsilon_1$ arises.
→When electric current $I _2$ flows through $C _2$, total magnetic flux linked with coil $C _1$ having $N _1$ turns is $N _1 \phi_1 \propto I _2$
$\therefore N _1 \phi_1= M I _2$
Where, M is mutual inductance
→For current changing with time,
$\frac{d}{d t}\left(N_1 \phi_1\right)= M \frac{d}{d t}\left( I _2\right)$
→According to Faraday's law, induced emf in $C _1$
$\varepsilon_1=-\frac{d}{d t}\left(N_1 \phi_1\right)$
→From equation (2) and (3),
$\varepsilon_1=- M \frac{d I _2}{d t}$
→Equation (4) is the required result.
→Here, value of induced emf depends on time rate of change of electric current and mutual inductance.
→In the figure, arrangement of two coil experiment is shown. Here, coils $C _1$ and $C _2$ are placed coaxially.
→When electric current $I _2$ passing through coil $C _2$ changes, magnetic flux linked with coil $C _1$ changes and hence induced emf $\varepsilon_1$ arises.
→When electric current $I _2$ flows through $C _2$, total magnetic flux linked with coil $C _1$ having $N _1$ turns is $N _1 \phi_1 \propto I _2$
$\therefore N _1 \phi_1= M I _2$
Where, M is mutual inductance
→For current changing with time,
$\frac{d}{d t}\left(N_1 \phi_1\right)= M \frac{d}{d t}\left( I _2\right)$
→According to Faraday's law, induced emf in $C _1$
$\varepsilon_1=-\frac{d}{d t}\left(N_1 \phi_1\right)$
→From equation (2) and (3),
$\varepsilon_1=- M \frac{d I _2}{d t}$
→Equation (4) is the required result.
→Here, value of induced emf depends on time rate of change of electric current and mutual inductance.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
- Write two main observations of photoelectric effect experiment which could only be explained by Einstein’s photoelectric equation.
- Draw a graph showing variation of photocurrent with the anode potential of a photocell.
An electroplating unit plates 3.0g of silver on a brass plate in 3.0 minutes. Find the current used by the unit. The electrochemical equivalent of silver is $1.12 × 10^{-6}\ kg\ C^{-1}$.
→Define the term ‘linearly polarised light’.
When’ does the intensity of transmitted light become maximum, when a polaroid sheet is rotated between two crossed polaroids?
When’ does the intensity of transmitted light become maximum, when a polaroid sheet is rotated between two crossed polaroids?
X-rays of wavelength $'\lambda'$ fall on a photosensitive surface, emitting electrons. Assuming that the work function of the surface can be neglected, prove that the de Broglie wavelength of electrons emitted will be $\sqrt{\frac{\text{h}\gamma}{2\text{mc}}}.$
→A filter transmits only the radiation of wavelength greater than 440nm. Radiation from a hydrogen-discharge tube goes through such a filter and is incident on a metal of work function 2.0eV. Find the stopping potential which can stop the photoelectrons.
The selling rate of a radioactive isotope is decided by its activity. What will be the second-hand rate of a one month old $\text{ }^{32}\text{P}\big(\text{t}_{\frac{1}{2}}=14.3\text{days}\big)$ source if it was originally purchased for 800 rupees?
→Protons with kinetic energy K emerge from an accelerator as a narrow beam. The beam is bent by a perpendicular magnetic field, so that it just misses a plane target kept at a distance l in front of the accelerator. Find the magnetic field.
Lenz's law is a specific statement of law of conservation of energy-Explain.
Write a short note : Size of the nucleus
###
How the radius of the nucleus is estimated?
Explain.
###
How the radius of the nucleus is estimated?
Explain.
Answer the following question:
Ray optics is based on the assumption that light travels in a straight line. Diffraction effects (observed when light propagates through small apertures/slits or around small obstacles) disprove this assumption. Yet the ray optics assumption is so commonly used in understanding location and several other properties of images in optical instruments. What is the justification?
Ray optics is based on the assumption that light travels in a straight line. Diffraction effects (observed when light propagates through small apertures/slits or around small obstacles) disprove this assumption. Yet the ray optics assumption is so commonly used in understanding location and several other properties of images in optical instruments. What is the justification?