Question
Explain structure and bonding of diborane.

Answer

  • Electronic configuration of boron is $1s^2 2s^2 2p^1.$ Thus, it has only three valence electrons.
  • In diborane, each boron atom is $sp^3$ hybridized. Three of such hybrid orbitals are half filled while the fourth $sp3$ hybrid orbital remains vacant.
  • The two half-filled $sp^3$ hybrid orbitals of each $B$ atom overlap with $1s$ orbitals of two terminal H atoms and form four $B – H$ covalent bonds. These bonds are also known as two-centred-two-electron $(2c-2e)$ bonds.
  • When $‘1s’$ orbital of each of the remaining two $H$ atoms simultaneously overlap with half-filled hybrid orbital of one B atom and the vacant hybrid orbital of the other $B$ atom, it produces two three-centred-two- electron bonds $(3c-2e)$ or banana bonds.
  • Hydrogen atoms involved in $(3c-2e)$ bonds are the bridging $H$ atoms i.e., $H$ atoms in two $B – H – B$ bonds.
  • In diborane, two $B$ atoms and four terminal $H$ atoms lie in one plane, while the two bridging H atoms lie symmetrically above and below this plane.
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