Question
Explain the following cases giving appropriate reasons:
  1. Nickel does not form low spin octahedral complexes.
  2. The $\pi-$ complexes are known for the transition metals only.
  3. $Co^{2+}$ is easily oxidised to $Co^{3+}$ in the presence of a strong ligand.

Answer

  1. Because two inner $d-$ orbitals are not available in $Ni$.
  2. Because only $d-$ electrons can be involved in $ð-$ complex.
  3. Because crystal field splitting energy is more than compensated for the third ionisation enthalpy.

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