Question
Explain the lateral shift for a ray refracted from a glass slab with parallel sides.
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Answer
→As shown in figure ray is incident on a rectangular slab at an angle $i_1$ and is refracted through an angle $r_1$ and travels through the glass slab.
→This ray is incident on the other surface of the slab at an angle $i_2$.
→From this point a ray emerges at an angle $r_2$. Here, $i_1=r_2$ can be easily proved from Snell's law.
→Here, emergent ray is parallel to incident ray. Thus there is no deviation of incident ray.
→The perpendicular distance between the incident ray and the emergent ray is called lateral shift.
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