Question
Explain the magnetic properties of $[Ni(CN_4)]^{2–}$.
✓
Answer
Magnetic properties of $[Ni(CN_4)]^{2–}$:
- In $\left[ Ni \left( CN _4\right)\right]^{2-}$ ion, $Ni ^{2+}$ undergoes $dsp ^2$ hybridization.
- Four vacant $dsp ^2$ hybrid orbitals of $Ni ^{2+}$ overlap with four orbitals of $CN ^{-}$ions to form $Ni - CN$ coordinate bonds. Configuration after the complex formation becomes:
- The complex has no unpaired electrons and hence, diamagnetic.
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