Question
Explain, the nature of $S - O$ bond in $SO _2$.

Answer

In $SO_2,$ sulphur atom is $sp^2$^ hybridised forming three hybrid orbitals.
In $SO_2,$ each oxygen atom is bonded to sulphur by a $\sigma $ and a $\pi $ bond. Hence in $SO_2$ there are two \sigma and two $\pi$ bonds.
a bonds are formed by $sp^2-p$ overlap while one of n bonds is due to $p\pi -p\pi $ overlaps and other is due to $p\pi -p\pi $ overlap.
But both $S-O$ bonds are identical due to resonance and has bond length $143 \ pm.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free