Question
Explain the principle of heat exchange. Ans. Suppose two objects $A$ and $B$ at different temperature $T_1$ and $T_2$ respectively are enclosed in a box of heat resistant material as shown in figure.

Answer


Image
Let $m _1=$ mass of $A , m _2=$ mass of $B _{,} c _1=$ specific heat capacity of $A _1 C _2=$ specific heat capacity of $B$ and $T=$ common temperature attained by $A$ and $B$ after the heat exchange between $A$ and $B$. Here, no heat leaves the box or enters the box from outside. Hence, if $T_1$ $>T_2$, heat energy lost by $A\left(Q_1\right)=$ heat energy gained by $B\left(Q_2\right)$.
$
\therefore m _1 c _1\left( T _1- T \right)= m _2 c _2\left( T - T _2\right)
$
[Note: If $m_1, c_1, T_1, T, m_2$ and $T_2$ are known, $c_2$ can be determined.]

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