Question
Explain the relation between osmotic pressure and concentration of solution.
✓
Answer
(1) Consider $V dm ^3$ of a solution in which $n _1$ moles of a solvent contains $n _2$ moles of a nonvolatile solute at absolute temperature $T$.
(2) The osmotic pressure, $n$ of a solution is given by,
$\pi=\frac{n R T}{V}$
$R$ is gas constant having value $0.08206 dm ^3 atm K ^{-1} mol ^{-1}$ ( $OR L atm K Kol ^{-1} mol ^{-1}$ ). Since
$\begin{aligned}
& C =\frac{n}{V} mol dm ^{-3} \text { or } M \\
& \therefore \pi= CRT
\end{aligned}$
(If concentration $C$ is expressed in $mol m ^{-3}$ and $R =8.314 J K ^{-1} mol ^{-1}$, then $\pi$ will be in $SI$ units, pascals or $Nm ^{-2}$.)
(2) The osmotic pressure, $n$ of a solution is given by,
$\pi=\frac{n R T}{V}$
$R$ is gas constant having value $0.08206 dm ^3 atm K ^{-1} mol ^{-1}$ ( $OR L atm K Kol ^{-1} mol ^{-1}$ ). Since
$\begin{aligned}
& C =\frac{n}{V} mol dm ^{-3} \text { or } M \\
& \therefore \pi= CRT
\end{aligned}$
(If concentration $C$ is expressed in $mol m ^{-3}$ and $R =8.314 J K ^{-1} mol ^{-1}$, then $\pi$ will be in $SI$ units, pascals or $Nm ^{-2}$.)
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