Question
Explain the structure and classification of animes.
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| | Column I (Property) | | Column II (Element) |
| (i) | Lanthanoid which shows +4 oxidation state | (a) | Pm |
| (ii) | Lanthanoid which can show +2 oxidation state | (b) | Ce |
| (iii) | Radioactive lanthanoid | (c) | Lu |
| (iv) | Lanthanoid which has 4f7 electronic configuration in +3 oxidation state | (d) | Eu |
| (v) | Lanthanoid which has 4f14 electronic configuration in +3 oxidation state | (e) | Gd |
| | | (f) | Dy |
i. $\text{MnO}_{4(aq)}^{-}+\text{S}_{2}\text{O}_{3(aq)}^{2-}+\text{H}_{2}\text{O}_{(l)}\rightarrow$
ii. $\text{Cr}_{2}\text{O}^{-}_{7(aq)}+\text{H}_{2}\text{S}_{(g)}+\text{H}^{+}_{(aq)}\rightarrow$
| Column I | Column II | ||
| i. | Mass percentage | a. | $\frac{\text{Number of moles of the solute component}}{\text{Volume of solution in litres}}$ |
| ii. | Volume percentage | b. | $\frac{\text{Number of moles of a component}}{\text{Total number of moles of all the components}}$ |
| iii. | Mole fraction | c. | $\frac{\text{Volume of the solute component in solution}}{\text{Total volume of solution}}\times100$ |
| iv. | Molality | d. | $\frac{\text{Mass of the solute component in solution}}{\text{Total mass of the solution}}\times100$ |
| v. | Molarity | e. | $\frac{\text{Number of moles of the solute components}}{\text{Mass of solvent in kilograms}}$ |