Question
Explain the variation of acceleration, velocity and distance with time for an object under free fall.
✓
Answer
- For a free falling object, considering the downward direction as negative, the object is released from rest.
$\therefore$ initial velocity $u =0$ and $a =- g =-9.8 m / s ^2$
$\therefore$ The kinematical equations become,
$v=u+a t=0-g t=-g t=-9.8 t$
$s = ut +\frac{1}{2} \text { at } 2= o +\frac{1}{2}(- g ) t ^2=-\frac{1}{2} 9.8 t ^2$
$=-4.9 t ^2$
$v ^2= u ^2+2 as =0+2(- g ) s$
$=-2 gs =-2 \times 9.8 s$
$=-19.6 s$ - These equations give the velocity and the distance travelled as a function of time and also the variation of velocity with distance.
- The variation of acceleration, velocity and distance with the time is as shown in figure $a, b$ and $c$ respectively.
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