Question
Explain the water of Crystallization.


Answer

- Take some crystals of blue vitriol (CuSO $\left.Cu _4 .5 H _2 O \right)$ in a test tube. Heat the test tube on a low flame of a burner. - It was observed that on heating, the crystalline structure of blue vitriol broke down to form a colourless powder and water came out. - This water was part of the crystal structure of blue vitriol. It is called water of crystallization. - On adding water to the white powder a solution
Image

was formed which had the same colour as the solution in the first test tube.
- From this we come to know that no chemical change has occurred in the crystals of blue vitriol due to heating.
- Losing water on heating blue vitriol, breaking down of the crystal structure, losing blue colour and regaining blue colour on adding water are all physical changes. $CuSO _4 \cdot 5 H _2 O \stackrel{\text { Heat }}{\longrightarrow} CuSO _4+5 H _2 O$
(Blue)
(White)
(anhydrous copper sulphate)
- Similarly, ferrous Sulphate crystals also contain 7 molecules of water of crystallization which are lost on heating.
- The reaction is represented as
$
\begin{aligned}
& FeSO _4 .7 H _2 O \stackrel{\text { Heat }}{\longrightarrow} FeSO _4+7 H _2 O \\
& \text { (Green) } \\
&
\end{aligned}
$
(anhydrous ferrous sulphate)
- Ionic compounds are crystalline in nature. These crystals are formed as a result of definite arrangement of ions.
- In the crystals of some compounds, water molecules are also included in this arrangement.
- That is the water of crystallization. The water of crystallization is present in a definite proportion of the chemical formula of the compound.

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