Question
Explain with example why the radii of isoelectronic species vary.

Answer

$i.$ The radii of isoelectronic species vary according to actual nuclear charge. Larger nuclear charge exerts greater attraction on the electrons and thus, the radius of that isoelectronic species becomes smaller.
$ii.$ For example, $F^–$ and $Na^+$ both have $10$ electrons but the nuclear charge on $F^–$ is $+9$ which is smaller than that of $Na^+$ which has the nuclear charge $+11.$
Hence, $F$ has larger ionic radii $(133 \ pm)$ than $Na^+ \ (98 \ pm).$

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