Question
Express $\frac{27}{64}$ and $\frac{-27}{64}$ as powers of a rational number.

Answer

$\because$ $27=3\times3\times3=3^3$
$(-27)=(-3)\times(-3)\times(-3)=(-3)^3$ and
$64=4\times4\times4=4^3$
$\therefore \frac{27}{64}=\frac{3^3}{4^3}=\Big(\frac{3}{4}\Big)^3$ and
$\frac{-27}{64}=\frac{(-3)^3}{(4)^3}=\Big(\frac{-3}{4}\Big)^3$

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