Question
Express $-40^{\circ} C$ on the Fahrenheit scale.
✓
Answer
$\begin{aligned} & \mathrm{F}=\frac{9}{5} \mathrm{C}+32 \\ & =\frac{9}{5} \times(-40)+32=-40^{\circ} \mathrm{F} \\ & \Rightarrow-40^{\circ} \mathrm{C}=-40^{\circ} \mathrm{F}\end{aligned}$
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