Question
Express the complex numbers $(1 - i)^4$ in the form of a + ib.
✓
Answer
$(1-i)^4=\left[(1-i)^2\right]^2$
$=\left(1+i^2-2 i\right)^2$
$=(1-1-2 i)^2=(-2 i)^2$
$=4 i^2=4 \times-1=-4$
$=\left(1+i^2-2 i\right)^2$
$=(1-1-2 i)^2=(-2 i)^2$
$=4 i^2=4 \times-1=-4$
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