Question
Express the following as a rational number: $\Big(\frac{-3}{4}\Big)^{-3}$
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Answer
$\Big(\frac{-3}{4}\Big)^{-3}=\Big(\frac{-4}{3}\Big)^3$ $=\Big(\frac{-4}{3}\Big)\times\Big(\frac{-4}{3}\Big)\times\Big(\frac{-4}{3}\Big)$ $=\frac{(-4)\times(-4)\times(-4)}{3\times3\times3}$ $=\frac{-64}{27}$
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