Question
Express the following complex numbers in the standard form a + ib:
$(1+\text{i})(1+2\text{i})$

Answer

$(1+\text{i})(1+2\text{i})=1\times(1+2\text{i})+\text{i}(1+2\text{i})$
$=1+2\text{i}+\text{i}+2\text{i}^2$
$=1+3\text{i}-2$
$=-1+3\text{i}$
$\therefore \ (1+\text{i})(1+2\text{i})=-1+3\text{i}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free