Question
Express the following exponential equations in logarithmic form:

$3^{-4}=\frac{1}{81}$

Answer

$\quad 3^{-4}=\frac{1}{81}$
$\therefore \quad-4=\log _3\left(\frac{1}{81}\right) \ldots$ [By definition of logarithm] i.e., $\log _3\left(\frac{1}{81}\right)=-4$

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