Question
Express the following exponential equations in logarithmic form:

$e ^2=7.3890$

Answer

$e ^2=7.3890$
$\therefore \quad 2=\log _e(7.3890) \ldots$ [By definition of logarithm] i.e., $\log _e(7.3890)=2$
(e is a mathematical constant, whose value is approximately 2.71828 )

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