Question
Express the following in power notation: $\Big(\frac{-3}{2}\Big)^4$

Answer

$\Big(\frac{-3}{2}\Big)^4=\frac{-3}{2}\times\frac{-3}{2}\times\frac{-3}{2}\times\frac{-3}{2}$ $=\frac{(-3)\times(-3)\times(-3)\times(-3)}{2\times2\times2\times2}$ $=\frac{81}{16}$

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