Question
f: N → N given by f(x) = x3

Answer

f: R → R is given by,

f(x) = x3

It is seen that for $\text{x},\text{y}\in\text{N},$ f(x) = f(y) ⇒ x3 = y3 ⇒ x = y.

$\therefore$ f is injective.

Now, $2\in\text{N}.$ But, there does not exist any element x in domain N
 such that f(x) = x3 = 2.

$\therefore$ f is not surjective.

Hence, function f injective but not surjective.

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