Question
f: R → R given by f(x) = x2

Answer

f: R → R is given by,
f(x) = x2
It is seen that f(-1) = f(1) = 1, but $-1\neq1.$
$\therefore$ f is not injective.
Now, $-2\in\text{R}.$ But, there does not exist any element $\text{x}\in\text{R}$ such that f(x) = x2 = -2.
$\therefore$ f is not surjective.
Hence, function f is neither injective nor surjective.

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