Factories: a^2+ 14a + 48 - Vidyadip

Question

Factories:
$a^2+ 14a + 48$

✓

Answer

To factories $a^2+ 14a + 48$, we will find two number $p$ and $q$ such that $p + q = 14$ and $pq = 48$
$8 + 6 = 14$ And $8 x 6 = 48$
Splittiong the middle term $14a$ in the given quadratic as $8a + 6a,$ we get:
$a^2+ 14a + 48 =a^2+ 8a + 6a + 48$
$= (a2 + 8a) + (6a + 48)$
$= a(a + 8) + 6(a + 8)$
$= (a + 6)(a + 8)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Marks Questions" from Factorization→Factorization — all question types→MATHS STD 8 question papers→Gujarat Board STD 8 question papers→Gujarat Board question paper generator→

Similar questions

If a number ends in 0, 1, 4, 5, 6, or 9, is it always a square?

Divide $\text{y}^4-3\text{y}^4+\frac{1}{2}\text{y}^2\text{ by }3\text{y}.$

Factorise the following, using the identity $a^2+ 2ab + b^2= (a + b)^2$
$ 4 x^4+12 x^3+9 x^2 $

Is $392$ a perfect cube? If not, find the smallest natural number by which $392$ must be multiplied so that the product is a perfect cube.

Express: $4 : 5$ as a percentage:

How many natural numbers lie between
(i) $9^2$ and $10^2?$ $\quad$ (ii) $11^2$ and $12^2?$

Replace $A, B, C$ by suitable numerals:

Factorize of the following algebraic expressions: $5(x - 2y) + 3(x - 2y)$

Express the following as the sum of two consecutive integers.
(i) $21^2$ $\quad$ (ii) $13^2$ $\quad$ (iii) $11^2$$\quad$(iv) $19^2$

Verify whether the given statement is true or false: $\frac{13}{5}\div\frac{26}{10}=\frac{26}{10}\div\frac{13}{5}$