Question
Factories:
$a^2- 14a - 51$

Answer

To factories $a^2- 14a - 51,$ we will find two number p and q such that $p + q = -14$ and $pq = -51$
Now,
$3 + (-17) = -14$ And $3 x (-17) = -51$
Splittiong the middle term -14 in the given quadratic as $3a - 17a,$ we get:
$a^2- 14a - 51 = a^2+ 3a - 17a - 51$
$= (a^2+ 3a) - (17a + 51)$
$= a(a + 3) - 17(a + 3)$
$= (a - 17)(a + 3)$

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