Maharashtra BoardEnglish MediumSTD 8MathsFactorization3 Marks
Question
Factories:
$a^2+3 a-88$
✓
Answer
To factories $a^2+3 a-88$, we will find two numbers $p$ and $q$ such that $p+q=3$ and $p q=-88$
Now, $11+(-8)=3$
And $11 \times(-8)=-88$
Splitting the middle term $3 a$ in the given quadratic as $11 a-8 a$, we get:
$a^2+3 a-88=a^2+11 a-8 a-88$
$=\left(a^2+11 a\right)-(8 a+88)$
$=a(a+11)-8(a+11)$
$=(a-8)(a+11)$
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