Question
Factories:$x^2-22 x+120$
✓
Answer
To factories $x^2-22 x+120$, we will find two number $p$ and $q$ such that $p+q=-22$ and $p q=120$
Now,
$(-12)+(-10)=-22 \text { And }(-22) \times(-10)=120$
Splittiong the middle term $14 x$ in the given quadratic as $-12 x-10 x$, we get:
$x^2-22 x+12=x^2-12 x-10 x+120$
$=\left(x^2-12\right)+(-10 x+120)$
$= x(x - 12) - 10(x - 12)$
$= (x - 10)(x - 12)$
Now,
$(-12)+(-10)=-22 \text { And }(-22) \times(-10)=120$
Splittiong the middle term $14 x$ in the given quadratic as $-12 x-10 x$, we get:
$x^2-22 x+12=x^2-12 x-10 x+120$
$=\left(x^2-12\right)+(-10 x+120)$
$= x(x - 12) - 10(x - 12)$
$= (x - 10)(x - 12)$
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