Maharashtra BoardEnglish MediumSTD 8MathsFactorization3 Marks
Question
Factories:
$x^2-22 x+120$
✓
Answer
To factories $x ^2-22 x +120$, we will find two number p and q such that $p + q =-22$ and $pq =120$
Now,
$(-12)+(-10)=-22 \text { And }(-22) \times(-10)=120$
Splittiong the middle term 14 x in the given quadratic as $-12 x -10 x$, we get:
$x^2-22 x+12=x^2-12 x-10 x+120$
$=\left(x^2-12\right)+(-10 x+120)$
$=x(x-12)-10(x-12)$
$=(x-10)(x-12)$
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