Question
Factories:
$y^2+5 y-36$

Answer

To factories $y^2+5 y-36$, we will find two number $p$ and $q$ such that $p+q=5$ and $p q=-36$
Now,
$9+(-4)=5$
And
$9 \times(-4)=-36$
Splittiong the middle term $5 y$ in the given quadratic as $-4 y+9 y$, we get:
$y^2+5 y-36=y^2-4 y+9 y-36$
$=(y 2-4 y)+(9 y-36)$
$=y(y-4)+9(y-4)$
$=(y+9)(y-4)$

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