Question
Factorisation of $-3a2 + 3ab + 3ac$ is $3a(-a - b - c).$
✓
Answer
False.
Solution:
We have,
$-3a^2+ 3ab + 3ac = 3a(-a + b + c)$
Solution:
We have,
$-3a^2+ 3ab + 3ac = 3a(-a + b + c)$
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