Question
Factorise:
1 - 27a3
1 - 27a3
✓
Answer
1 - 27a3
= (1)3 - (3a)3
= (1 - 3a)[(1)2 + 1 × 3a + (3a)2] Since a3 - b3 = (a - b)(a2 + a × b + b2)
= (1 - 3a)(1 + 3a + 9a2)
= (1)3 - (3a)3
= (1 - 3a)[(1)2 + 1 × 3a + (3a)2] Since a3 - b3 = (a - b)(a2 + a × b + b2)
= (1 - 3a)(1 + 3a + 9a2)
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