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Factorisation — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSFactorisation2 Marks
Question
Factorise$ :1 - 8a^3$
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Answer

$1 - 8a^3$
$= (1)^3 - (2a)^3$
$= ( 1 - 2a )[ (1)^2 + 1 x 2a + (2a)^2 ]$
$[ \because a^3 - b^3 = ( a - b )( a^2 + ab + b^2 )]$
$= ( 1 - 2a )[ 1 + 2a + 4a^2 ]$

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