Question
Factorise:
108a2 - 3(b - c)2
108a2 - 3(b - c)2
✓
Answer
108a2 - 3(b - c)2
= 3[(36a2 - (b -c)2]
= 3[(6a)2 - (b - c)2] $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
= 3(6a + b - c)(6a - b + c)
= 3[(36a2 - (b -c)2]
= 3[(6a)2 - (b - c)2] $\big[\therefore\ \text{a}^2-\text{b}^2=(\text{a}-\text{b})(\text{a}+\text{b})\big]$
= 3(6a + b - c)(6a - b + c)
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