Question
Factorise:
$108 a^2-3(b-c)^2$
$108 a^2-3(b-c)^2$
✓
Answer
$108 a^2-3(b-c)^2$
$=3\left[\left(36 a^2-(b-c)^2\right]\right.$
$=3\left[(6 a)^2-(b-c)^2\right]\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=3(6 a+b-c)(6 a-b+c)$
$=3\left[\left(36 a^2-(b-c)^2\right]\right.$
$=3\left[(6 a)^2-(b-c)^2\right]\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=3(6 a+b-c)(6 a-b+c)$
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