Factorise: 12(2 x-3 y)^2-16(3 y-2 x) - Vidyadip

Question

Factorise: $12(2 x-3 y)^2-16(3 y-2 x)$

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Answer

$12(2 x-3 y)^2-16(3 y-2 x)$
$=12(2 x-3 y)^2+16(2 x-3 y)$
$ = 4(2x - 3y){3(2x - 3y) + 4} $
$= 4(2x - 3y)(6x - 9y + 4)$

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