Factorise: 14x^3 + 21x^4y - 28x^2y^2 - Vidyadip

Question

Factorise:
$14x^3 + 21x^4y - 28x^2y^2$

✓

Answer

$14x^3 + 21x^4y - 28x^2y^2$
$= 14x^2(2x + 3x^2y - 4y^2)(HCF $ of $ 14, 21, 28 = 7)$

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