Factorise: 16 p^3-4 p - Vidyadip

Question

Factorise:
$16 p^3-4 p$

✓

Answer

$16 p^3-4 p$
$= & 4 p\left[4 p^2-1\right]$
$= & 4 p(2 p)^2-(1)^2$
$= & 4 p(2 p+1)(2 p-1)$

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