Factorise: 16x^4 - 1 - Vidyadip

Question

Factorise: $16x^4 - 1$

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Answer

$16x^4 - 1$
$= (4x^2)^2 - (1)^2$
$= (4x^2 - 1)(4x^2 + 1)$
$= [(2x)^2 - (1)^2](4x^2 + 1)$
$= (2x - 1)(2x + 1)(4x^2 + 1)$

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