Question
Factorise:
$27 a^3+64 b^3$

Answer

$27 a^3+64 b^3$
$=(3 a)^3+(4 b)^3$
$=(3 a+4 b)\left[(3 a)^2-(3 a)(4 b)+(4 b)^2\right]$
$=(3 a+4 b)\left(9 a^2-12 a b+16 b^2\right)$

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