Question
Factorise: $ (2 a+3 b)^2-16 c^2$
✓
Answer
$ (2 a+3 b)^2-16 c^2$
$ =(2 a+3 b) 2-(4 c)^2 $
$ =(2 a+3 b+4 c)(2 a+3 b-4 c) $
$ \{\because a 2-b 2=(a+b)(a-b)\} $
$ =(2 a+3 b) 2-(4 c)^2 $
$ =(2 a+3 b+4 c)(2 a+3 b-4 c) $
$ \{\because a 2-b 2=(a+b)(a-b)\} $
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