Question
Factorise:
$(2 a+3 b)^2-16 c^2$
 

Answer

$(2 a+3 b)^2-16 c^2$
$=(2 a+3 b) 2-(4 c)^2$
$=(2 a+3 b+4 c)(2 a+3 b-4 c)$
$\{\because a 2-b 2=(a+b)(a-b)\}$​​​​​​​

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