Question
Factorise:
$2 a+6 b-3(a+3 b)^2$

Answer

$2 a+6 b-3(a+3 b)^2$
$=2(a+3 b)-3(a+3 b)^2$
$=(a+3 b)\{2-3(a+3 b)\}$
$=(a+3 b)(2-3 a-9 b)$

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